From 5eead8bc42d81caff222d68fcb949cb9720552fe Mon Sep 17 00:00:00 2001 From: =?UTF-8?q?Oliver=20Gro=C3=9F?= Date: Tue, 8 Jul 2008 12:48:38 +0200 Subject: [PATCH] [vorlesung] rechenfehler gefixt --- kapII-5.tex | 4 ++-- 1 file changed, 2 insertions(+), 2 deletions(-) diff --git a/kapII-5.tex b/kapII-5.tex index 7476d49..4e9e49b 100644 --- a/kapII-5.tex +++ b/kapII-5.tex @@ -224,8 +224,8 @@ daraus ergibt sich \begin{align} \frac{1}{\sqrt{2}} \left( \hat{x} + i\hat{p} \right) \ket{0} &= \zero &\left| \bra{x} \right.\\ \dirac{x}{\hat{x} + i\hat{p}}{0} &= 0\\ - x + i(-i) \diffPs{x} \phi_0(x) &= 0 &\left(\text{denn: } \dirac{x}{\hat{p}}{\psi} = -i \hbar \diffPs{x} \psi(x) \right)\\ - \rightarrow \left(x - \diffPs{x} \right) \phi_0(x) &= 0\\ + \left(x + i(-i) \diffPs{x}\right) \phi_0(x) &= 0 &\left(\text{denn: } \dirac{x}{\hat{p}}{\psi} = -i \hbar \diffPs{x} \psi(x) \right)\\ + \rightarrow \left(x + \diffPs{x} \right) \phi_0(x) &= 0\\ \phi_0(x) &= c \cdot e^{-\frac{x^2}{2}} \end{align} Normierung: