\usepackage{amsmath} %\usepackage{mathtools} \usepackage{bbm} \newcommand{\set}[1]{\left\lbrace #1 \right\rbrace } \newcommand{\setZ}{\mathbbm{Z}} \newcommand{\setN}{\mathbbm{N}} \newcommand{\setQ}{\mathbbm{Q}} \newcommand{\setR}{\mathbbm{R}} \newcommand{\setC}{\mathbbm{C}} \newcommand{\einsmatrix}{\mathbbm{1}} \newcommand{\bigO}{\mathbbm{O}} \newcommand{\inlinematrix}[1]{\begin{pmatrix} #1 \end{pmatrix}} \newcommand{\inlinematrixu}[1]{\begin{matrix} #1 \end{matrix}} \newcommand{\inlinematrixd}[2]{\left( \begin{matrix} #1\vphantom{#2} \end{matrix} ~\right| \left. \begin{matrix} \vphantom{#1}#2 \end{matrix} \right)} \newcommand{\inlinematrixdet}[1]{\begin{vmatrix} #1 \end{vmatrix}} \newcommand{\norm}[1]{\left\Vert #1 \right\Vert} \newcommand{\scalar}[2]{\langle #1 , #2 \rangle} \newcommand{\abs}[1]{{\left| #1 \right|}} \newcommand{\gdw}{\Leftrightarrow} %\newcommand{\iff}{\Leftrightarrow} \newcommand{\re}[1]{{\text{Re}\left( #1 \right)}} \newcommand{\im}[1]{{\text{Im}\left( #1 \right)}} \newcommand{\tr}{{\text{tr}}} \newcommand{\sign}{{\text{sign}}} \newcommand{\QED}{\begin{large}\textbf{\checkmark}\end{large}} \newcommand{\cequiv}{\stackrel{\scriptscriptstyle\wedge}{=}} %ContextEQUIvalent \newcommand{\deq}{\stackrel{!}{=}} \newcommand{\expval}[1]{\langle #1 \rangle} \newcommand{\diffP}[1]{\frac{\partial}{\partial #1}} \newcommand{\diffT}[1]{\frac{\text{d}}{\text{d} #1}} \newcommand{\diffTfrac}[2]{\frac{\text{d} #1}{\text{d} #2}} \newcommand{\diffTm}[3]{\diffTfrac{^{#1} #2}{#3^{#1}}} \newcommand{\diffPfrac}[2]{\frac{\partial #1}{\partial #2}} \newcommand{\intgr}[4]{\int_{#1}^{#2} #3 ~\text{ d}#4} \newcommand{\intgru}[2]{\int #1 ~\text{ d}#2} \newcommand{\intgrinf}[2]{\intgr{-\infty}{+\infty}{#1}{#2}} \newcommand{\sbk}[1]{\left( #1 \right)} \newcommand{\sqbk}[1]{\left[ #1 \right]} \newcommand{\detb}[1]{\det\sqbk{#1}} \newcommand{\cosb}[1]{\cos\sbk{#1}} \newcommand{\sinb}[1]{\sin\sbk{#1}} \newcommand{\levicivita}[1]{\varepsilon_{#1}} \newcommand{\krondelta}[1]{\delta_{#1}} \newcommand{\equationblock}[1]{\begin{equation} #1 \end{equation}}