[vorlesung] rechenfehler gefixt
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@ -224,8 +224,8 @@ daraus ergibt sich
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\begin{align}
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\begin{align}
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\frac{1}{\sqrt{2}} \left( \hat{x} + i\hat{p} \right) \ket{0} &= \zero &\left| \bra{x} \right.\\
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\frac{1}{\sqrt{2}} \left( \hat{x} + i\hat{p} \right) \ket{0} &= \zero &\left| \bra{x} \right.\\
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\dirac{x}{\hat{x} + i\hat{p}}{0} &= 0\\
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\dirac{x}{\hat{x} + i\hat{p}}{0} &= 0\\
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x + i(-i) \diffPs{x} \phi_0(x) &= 0 &\left(\text{denn: } \dirac{x}{\hat{p}}{\psi} = -i \hbar \diffPs{x} \psi(x) \right)\\
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\left(x + i(-i) \diffPs{x}\right) \phi_0(x) &= 0 &\left(\text{denn: } \dirac{x}{\hat{p}}{\psi} = -i \hbar \diffPs{x} \psi(x) \right)\\
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\rightarrow \left(x - \diffPs{x} \right) \phi_0(x) &= 0\\
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\rightarrow \left(x + \diffPs{x} \right) \phi_0(x) &= 0\\
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\phi_0(x) &= c \cdot e^{-\frac{x^2}{2}}
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\phi_0(x) &= c \cdot e^{-\frac{x^2}{2}}
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\end{align}
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\end{align}
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Normierung:
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Normierung:
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